An electric iron is rated at 1000watts, 250v. The corresponding maximum resistance and accompanying current is
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Correct Answer: Option D
Explanation:
R = \(\frac{V^2}{R}\) = IV ; R = \(\frac{V^2}{P}\) and I = \(\frac{P}{V}\)
R = \(\frac{(250)^2}{100}\) and I = R = \(\frac{1000}{250}\)
R = 62.5\(\Omega\) and I = 4A
R = \(\frac{V^2}{R}\) = IV ; R = \(\frac{V^2}{P}\) and I = \(\frac{P}{V}\)
R = \(\frac{(250)^2}{100}\) and I = R = \(\frac{1000}{250}\)
R = 62.5\(\Omega\) and I = 4A