A rod of length 10cm is heated through 100oC and its final length is 10.26cm. What is the co-efficient of linear expansion of the rod?
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Correct Answer: Option B
Explanation:
\(\alpha\) = \(\frac{L_2 - L_1}{L_1 \times \theta}\)
= \(\frac{10 - 26 - 10}{10 \times 100}\)
= 2.6 x 10-4oC
\(\alpha\) = \(\frac{L_2 - L_1}{L_1 \times \theta}\)
= \(\frac{10 - 26 - 10}{10 \times 100}\)
= 2.6 x 10-4oC