A heater marked 50W will evaporate 0.005kg of boiling water in 50 seconds. The specific latent heat of vaporization of water in J/kg is
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Correct Answer: Option E
Explanation:
Heat energy = Electrical energy
mL = power x time
0.005 x L = 50 x 50
L = 5 x 105J/kg
Heat energy = Electrical energy
mL = power x time
0.005 x L = 50 x 50
L = 5 x 105J/kg