a force of 16N applied 4.0kg block that is at rest on a smooth, horizontal surface. What is the velocity of the block at t = 5 seconds?
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Correct Answer: Option C
Explanation:
F = ma
= \(\frac{m(u - v)}{t}\)
16 = \(\frac{4(v - 0)}{5}\)
v = 20ms-1
F = ma
= \(\frac{m(u - v)}{t}\)
16 = \(\frac{4(v - 0)}{5}\)
v = 20ms-1