The difference of potential between the terminals of cells is 2.2 volts. When a 4ohm resistor is connected across the terminals of this cells, the potential difference is 2 volts. What is the internal resistance of the cell?
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Correct Answer: Option C
Explanation:
IR = 2 and Ir = 0.2
I = \(\frac{2}{R}\) ; I = \(\frac{0.2}{r}\)
\(\frac{2}{4}\) = \(\frac{0.2}{r}\)
r = 0.4\(\Omega\)
IR = 2 and Ir = 0.2
I = \(\frac{2}{R}\) ; I = \(\frac{0.2}{r}\)
\(\frac{2}{4}\) = \(\frac{0.2}{r}\)
r = 0.4\(\Omega\)