The lower and upper fixed points marked on a mecury-in-glass thermometer are 210mm apart. The end of the mercury column in the tube is 49mm above the lower fixed point in a room. What is the temperature of the room in degrees Celsius?
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Correct Answer: Option B
Explanation:
210mm .... 100oC
49mm .... \(\theta\)
0mm .... 0oC
\(\frac{49 - 0}{210 - 0}\) = \(\frac{\theta - 0}{100 - 0}\)
\(\frac{49}{210}\) = \(\frac{\theta}{100}\)
\(\theta\) = 23.3oC
210mm .... 100oC
49mm .... \(\theta\)
0mm .... 0oC
\(\frac{49 - 0}{210 - 0}\) = \(\frac{\theta - 0}{100 - 0}\)
\(\frac{49}{210}\) = \(\frac{\theta}{100}\)
\(\theta\) = 23.3oC