A plane inclined at an angle of 30o to the horizontal has an efficiency of 60%. The force parallel to the plane required to push a load of 120N uniformly up the plane is
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Correct Answer: Option B
Explanation:
V.R = \(\frac{1}{sin 30}\) = 2
Efficiency = \(\frac{m.A}{V.R}\) x 100%
60 = \(\frac{120}{effort}\) x \(\frac{1}{2}\) x 100
Effort = 100N
V.R = \(\frac{1}{sin 30}\) = 2
Efficiency = \(\frac{m.A}{V.R}\) x 100%
60 = \(\frac{120}{effort}\) x \(\frac{1}{2}\) x 100
Effort = 100N