A particle moves in a circular orbit of radius 0.02m. If the speed of the particle is 0.88ms-1, calculate its frequency in cycles per second
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Correct Answer: Option B
Explanation:
W = \(\frac{v}{r}\)
= \(\frac{0.88}{0.02}\) = 44 rad/s
2\(\pi\)F = W = 44
F = \(\frac{44}{2 \times 3.142}\)
= 7Hz
W = \(\frac{v}{r}\)
= \(\frac{0.88}{0.02}\) = 44 rad/s
2\(\pi\)F = W = 44
F = \(\frac{44}{2 \times 3.142}\)
= 7Hz