A gun of mass 2.0kg fires a bullet of mass 16 x 10 -2kg due East. If the bullet leaves the nozzle of the gun with a velocity of 150ms-1, what is the recoil velocity of the gun?
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Correct Answer: Option C
Explanation:
Gun momentum = bullet momentum
2 x v = 1.6 x 10-2 x 150
v = 1.2ms-1 in opposite direction
Gun momentum = bullet momentum
2 x v = 1.6 x 10-2 x 150
v = 1.2ms-1 in opposite direction