A simple pendulum with a period of 2.0s has its length doubled. Its new period is
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Correct Answer: Option D
Explanation:
Using \(\frac{T_1}{T_2}\) = \(\sqrt\frac{L_1}{L_2}\)
\(\frac{2}{T_2}\) = \(\sqrt\frac{L_1}{2L_1}\)
T2 = 2.83sec
Using \(\frac{T_1}{T_2}\) = \(\sqrt\frac{L_1}{L_2}\)
\(\frac{2}{T_2}\) = \(\sqrt\frac{L_1}{2L_1}\)
T2 = 2.83sec