A quantity of gas occupies a certain volume when the temperature is -73oC and the pressure is 1.5 atmospheres. If the pressure is increased to 4.5 atmospheres and the volume is halved at the same time, what will be the new temperature of the gas?
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Correct Answer: Option E
Explanation:
\(\frac{P_1V_1}{T_1}\) = \(\frac{P_2V_2}{T_2}\)
V1 = 2V2
\(\frac{1.5 \times 2V_2}{-73 + 273}\) = \(\frac{4.5 \times V_2}{T_2}\)
T2 = 300K = 27oC
\(\frac{P_1V_1}{T_1}\) = \(\frac{P_2V_2}{T_2}\)
V1 = 2V2
\(\frac{1.5 \times 2V_2}{-73 + 273}\) = \(\frac{4.5 \times V_2}{T_2}\)
T2 = 300K = 27oC