If the fundamental frequency of a closed pipe organ on a day when the speed of sound is 340ms-1 is 170Hz, then the length of the pipe is
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Correct Answer: Option A
Explanation:
\(\lambda\) = \(\frac{v}{f}\)
= \(\frac{340}{170}\)
= 2m ; for closed pipe
L = \(\frac{1}{4}\)\(\lambda\)
= \(\frac{1}{4}\) x \(\frac{2}{1}\)
= 0.5m
= 50cm
\(\lambda\) = \(\frac{v}{f}\)
= \(\frac{340}{170}\)
= 2m ; for closed pipe
L = \(\frac{1}{4}\)\(\lambda\)
= \(\frac{1}{4}\) x \(\frac{2}{1}\)
= 0.5m
= 50cm