A ball is thrown vertically into the air with an initial velocity u. What is the greatest height reached?
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Correct Answer: Option D
Explanation:
Using V2 = U2 - 2gS
V = 0ms-1 at greatest height
S = \(\frac{u^2}{2g}\)
Using V2 = U2 - 2gS
V = 0ms-1 at greatest height
S = \(\frac{u^2}{2g}\)