A lens of focal length 12.0cm forms an upright image three times the size of a real object. The distance between the object and the images is
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Correct Answer: Option D
Explanation:
F = 12cm, V = 3u
F = \(\frac{uv}{u + v}\)
12 = \(\frac{u\times 3u}{u + 3v}\)
u = 16cm, and v = 48cm
therefore, distance between u and v
v = 48 - 16 = 32cm
F = 12cm, V = 3u
F = \(\frac{uv}{u + v}\)
12 = \(\frac{u\times 3u}{u + 3v}\)
u = 16cm, and v = 48cm
therefore, distance between u and v
v = 48 - 16 = 32cm