A man clapping his hands at regular intervals observes that the echo of a clap coincides with the next clap. If the reflecting cliff is 160m away and the speed of sound is 320ms-1, what is the frequency of the clapping?
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option A
Explanation:
Total distance = 2 x 160 = 320cm
Total time = \(\frac{320}{320}\) = 1s
F = \(\frac{1}{1}\) = \(\frac{1}{1}\)
= 1Hz
Total distance = 2 x 160 = 320cm
Total time = \(\frac{320}{320}\) = 1s
F = \(\frac{1}{1}\) = \(\frac{1}{1}\)
= 1Hz