An elevator of mass 4800kg is supported by a cable which can safely withstand a maximum tension of 60 000N. The maximum upward acceleration the elevator can have is
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Correct Answer: Option A
Explanation:
a = \(\frac{F}{m}\)
= \(\frac{60000 -(4800 \times10)}{4800}\)
= 2.5ms-2
a = \(\frac{F}{m}\)
= \(\frac{60000 -(4800 \times10)}{4800}\)
= 2.5ms-2