Calculate the amount of heat required to convert 2kg of ice at 2oC to water at 0oC. [specific heat capacity of ice = 2090Jkg-1oC-1, specific latent heat of fusion of ice = 333kJkg-1]
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Correct Answer: Option D
Explanation:
Q = mL + mc\(\theta\)
= (2 x 333000) + (2 x 2090 x 2)
= 674 360J
Q = mL + mc\(\theta\)
= (2 x 333000) + (2 x 2090 x 2)
= 674 360J