A current of 0.5A flows through a resistor when connected to a 40-V battery. How much energy is dissipated in 2 minutes?
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Correct Answer: Option C
Explanation:
Electrical energy = IVT
= 0.5 x 40 x 2 x 60
= 2400J
Electrical energy = IVT
= 0.5 x 40 x 2 x 60
= 2400J