A galvanometer of resistance 20\(\Omega\) is to be provided with a shunt that \(\frac{1}{10}\) of the whole current in a circuit passes through the galvanometer. The resistance of the shunt is
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Correct Answer: Option B
Explanation:
\(\frac{1}{10}\)I x 20 = \(\frac{9}{10}\)I x Rs
Rs = 2.22\(\Omega\)
\(\frac{1}{10}\)I x 20 = \(\frac{9}{10}\)I x Rs
Rs = 2.22\(\Omega\)