A 20-toothed gear wheel drives a 60-toothed one. If the angular speed of the smaller wheel is 120 rev s-1, the angular speed of the larger wheel is
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Correct Answer: Option C
Explanation:
\(\frac{\text {speed of driver}}{\text {speeder driven}}\) = \(\frac{\text {no. of teeth of driver}}{\text {no. of teeth of driven}}\)
\(\frac{120}{V}\) = \(\frac{20}{60}\)
v = 360 rev s-1
\(\frac{\text {speed of driver}}{\text {speeder driven}}\) = \(\frac{\text {no. of teeth of driver}}{\text {no. of teeth of driven}}\)
\(\frac{120}{V}\) = \(\frac{20}{60}\)
v = 360 rev s-1