Two points on a velocity time-graph have coordinates (5s, 10ms-1) and (20s, 20ms-1). Calculate the mean acceleration between the two points
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Correct Answer: Option A
Explanation:
a = \(\frac{v - u}{\Delta t}\)
a = \(\frac{20 - 10}{20 - 5}\)
a = 0.67ms-1
a = \(\frac{v - u}{\Delta t}\)
a = \(\frac{20 - 10}{20 - 5}\)
a = 0.67ms-1