A piece of wood of mass 40g and uniform cross-sectional area of 2cm2 floats upright in water. The length of the wood immersed is
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Correct Answer: Option C
Explanation:
Mw displaced = 40g
density = \(\frac{mass}{\text{area x height}}\)
I = \(\frac{40}{2\times h}\)
h = 20cm
Mw displaced = 40g
density = \(\frac{mass}{\text{area x height}}\)
I = \(\frac{40}{2\times h}\)
h = 20cm