Three 2-µF capacitors are arranged as seen in the circuit above . The effective capacitance between E and F is
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Correct Answer: Option B
Explanation:
\(C_T = \frac{2 \times (2 + 2)}{2 + (2 + 2)}\)
= \(\frac{8}{6}\)
= 1.33 \(\mu\)F
\(C_T = \frac{2 \times (2 + 2)}{2 + (2 + 2)}\)
= \(\frac{8}{6}\)
= 1.33 \(\mu\)F