A car moving with a speed of 90kmh-1 was brought uniformly to rest by the application of the brakes in 10s. How far did the car travel after the brakes were applied?
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Correct Answer: Option C
Explanation:
speed = \(\frac{90 \times 10^3}{3600}\) = 25ms-1
distance = speed x time
= 25 x 10 = 250m
speed = \(\frac{90 \times 10^3}{3600}\) = 25ms-1
distance = speed x time
= 25 x 10 = 250m