What must be the distance between an object and a converging lens of focal length 20cm to produce an erect image two times the object height?
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Correct Answer: Option C
Explanation:
F = \(\frac{uv}{u + v}\); v = 2u
20 = \(\frac{ux - 2u}{u + (-2u)}\); u = 10cm
F = \(\frac{uv}{u + v}\); v = 2u
20 = \(\frac{ux - 2u}{u + (-2u)}\); u = 10cm