A body of weight W N rest on a smooth plane inclined at an angle\(\theta\)o to the horizontal. What is the resolved part of the weight in Newtons along the plane?
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Correct Answer: Option A
Explanation:
horizontal component = W cos(90o - \(\theta\))
= W sin[sup][/sup]
horizontal component = W cos(90o - \(\theta\))
= W sin[sup][/sup]