The mass of a stone is 15.0g when completely immersed in water and 10.0g when completely immersed in a liquid of relative density 2.0. The mass of the stone in air is
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Correct Answer: Option C
Explanation:
R.D = \(\frac{\text{ mass of liquid displaced}}{\text {mass of water displaced}}\)
2 = \(\frac{m - 10}{m - 15}\)
m = 20g
R.D = \(\frac{\text{ mass of liquid displaced}}{\text {mass of water displaced}}\)
2 = \(\frac{m - 10}{m - 15}\)
m = 20g