A brass rod is 2m long at a certain temperature. What is the length for a temperature rise of 100K, if the expansivity of brass is 18 x 10-6K-1?
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Correct Answer: Option A
Explanation:
\(\alpha\) = \(\frac{L_2 - L_1}{L_1 \times \Delta \theta}\)
18 x 10-6 = \(\frac{L_2 - 2}{2\times 100}\)
L = 2.0036m
\(\alpha\) = \(\frac{L_2 - L_1}{L_1 \times \Delta \theta}\)
18 x 10-6 = \(\frac{L_2 - 2}{2\times 100}\)
L = 2.0036m