An equipment whose power is 1500W and resistance is 375 ohms would draw a current of
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Correct Answer: Option B
Explanation:
P = I2R \(\Rightarrow\) I = \(\sqrt\frac{P}{R}\)
I = \(\sqrt\frac{1500}{375}\)
= 2A
P = I2R \(\Rightarrow\) I = \(\sqrt\frac{P}{R}\)
I = \(\sqrt\frac{1500}{375}\)
= 2A