A machine requires 1000J of work to raise a load of 500N through a vertical distance of 1.5m. Calculate the efficiency of the
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Correct Answer: Option B
Explanation:
\(\frac{500 \times 1.5}{100.0}\) x 100%
= 75%
\(\frac{500 \times 1.5}{100.0}\) x 100%
= 75%