A concave mirror has a radius of curvature of 36cm. At what distance from the mirror should an object be placed to give a real image three times the size of the object?
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Correct Answer: Option B
Explanation:
F = \(\frac{uv}{u + v}\)
v = 3u
18 = \(\frac{3u \times u}{3u + u}\)
u = 24cm
F = \(\frac{uv}{u + v}\)
v = 3u
18 = \(\frac{3u \times u}{3u + u}\)
u = 24cm