The external and internal diameter of a tube are measured as (32 ± 2)mm and (21 ± 1)mm respectively. Determine the percentage error in the thickness of the tube.
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Correct Answer: Option C
Explanation:
Actual thickness = 34 - 22 = 12
error thickness = 30 - 20 = 10
error = 12 - 10 = 2mm that is, (11 ± 1)mm
%error = \(\frac{1}{11}\) x \(\frac{100}{1}\)
= 9%
Actual thickness = 34 - 22 = 12
error thickness = 30 - 20 = 10
error = 12 - 10 = 2mm that is, (11 ± 1)mm
%error = \(\frac{1}{11}\) x \(\frac{100}{1}\)
= 9%