An object of mass 400g and density 600kgm-3 is suspended with a sting so that half of it is immersed in paraffin of density 900kgm-3. The tension in the string is
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Correct Answer: Option B
Explanation:
volume of object = \(\frac{400 \times 10^{-2}}{600}\)
= 0.00067m3
volume of paraffin displaced = \(\frac{1}{2}\) x 0.00067
= 0.00034m3
mass of paraffin = 900 x 34 x 10-5
= 0.3kg
weight of paraffin = 0.3 x 10
= 3N = upthrust = tension in the string
volume of object = \(\frac{400 \times 10^{-2}}{600}\)
= 0.00067m3
volume of paraffin displaced = \(\frac{1}{2}\) x 0.00067
= 0.00034m3
mass of paraffin = 900 x 34 x 10-5
= 0.3kg
weight of paraffin = 0.3 x 10
= 3N = upthrust = tension in the string