A force of 15N stretches a spring to a total length of 30cm. An additional force of 10N stretches the spring 5cm further. Find the natural length of the spring
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Correct Answer: Option B
Explanation:
\(\frac{15}{30 - L}\) = \(\frac{10}{5}\)
L = 22.5cm
\(\frac{15}{30 - L}\) = \(\frac{10}{5}\)
L = 22.5cm