The sound from a source travelled to the bottom of the sea and the echo was heard 4s later. If the speed of sound in sea water is 1500ms-1 the depth of the sea is
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Correct Answer: Option B
Explanation:
t = 4s ; v = 150ms-1
depth = X ; but 2X = vt
X = \(\frac {vt}{2}\) = \(\frac {1500 \times 4}{2}\)
X = 3000m
t = 4s ; v = 150ms-1
depth = X ; but 2X = vt
X = \(\frac {vt}{2}\) = \(\frac {1500 \times 4}{2}\)
X = 3000m