A pipe of length 45cm is closed at the end. Calculate the fundamental frequency of the sound wave generated in the pipe if the velocity of sound in air is 360ms-1 [Neglect end correction]
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Correct Answer: Option C
Explanation:
\(\lambda\) = 4L = 4 X 45 = 180cm
F = \(\frac {V}{\lambda}\)
= \(\frac {360}{180 \times 10^{-2}}\)
= 200Hz
\(\lambda\) = 4L = 4 X 45 = 180cm
F = \(\frac {V}{\lambda}\)
= \(\frac {360}{180 \times 10^{-2}}\)
= 200Hz