A capacitor 8\(\mu\)F is charged to a potential difference of 100V. The energy stored by the capacitor is
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Correct Answer: Option D
Explanation:
Energy = \(\frac{1}{2}\)CV2
= \(\frac{1}{2}\) x 8 x 10-6 x (100)2
= 4 x 10-2J
Energy = \(\frac{1}{2}\)CV2
= \(\frac{1}{2}\) x 8 x 10-6 x (100)2
= 4 x 10-2J