A body is projected from the earth's surface with the intention of letting it escape from the earth's gravitational field. What is the minimum escape velocity of the body? [Earth's radius = 6.4 x 103km, g = 10ms-2]
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Correct Answer: Option D
Explanation:
Velocity = \(\sqrt2gR\)
= 2 x 6400 x 100 x 10
= 11 km-1
Velocity = \(\sqrt2gR\)
= 2 x 6400 x 100 x 10
= 11 km-1