A hydraulic press has a large circular piston of radius 0.8m and a circular plunger of radius 0.2m. A force of 500N is exerted by the plunger. Find the force exerted on the piston
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Correct Answer: Option D
Explanation:
Pressure on piston = pressure on the plunger
\(\frac{500}{\pi\ \times\ 0.8 \times\ 0.8}\) = \(\frac{F}{\pi\ \times\ 0.2 \times\ 0.2}\)
F = 31.25N
F \(\approxeq\) 31N
Pressure on piston = pressure on the plunger
\(\frac{500}{\pi\ \times\ 0.8 \times\ 0.8}\) = \(\frac{F}{\pi\ \times\ 0.2 \times\ 0.2}\)
F = 31.25N
F \(\approxeq\) 31N