If the maximum voltage across a 100ohms resistor is 20V, then the maximum power it can dissipate is
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Correct Answer: Option B
Explanation:
P = \(\frac{V^2}{R}\)
= \(\frac{20 \times 20}{100}\)
= 4W
P = \(\frac{V^2}{R}\)
= \(\frac{20 \times 20}{100}\)
= 4W