A load of 20N on a wire of cross-sectional area 8 x 10-7m2, produces an extension of 10m2. calculate Young's modulus for the material of the wire if its length is 3m
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:
Young's modulus = \(\frac{F}{A}\) \(\div\) \(\frac{e}{L}\)
= \(\frac{20}{8 \times 10^{-7}}\) \(\div\) \(\frac{10^{-4}}{3}\)
= 7.5 x 1011Nm-2
Young's modulus = \(\frac{F}{A}\) \(\div\) \(\frac{e}{L}\)
= \(\frac{20}{8 \times 10^{-7}}\) \(\div\) \(\frac{10^{-4}}{3}\)
= 7.5 x 1011Nm-2