A mass of a liquid at 30oC is mixed with a mass of the same liquid at 70oC and the temperature of the mixture is 45oC. Find the ratio of the mass of the cold liquid to the mass of the other liquid.
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Correct Answer: Option B
Explanation:
Heat lost = heat gained
mH x c x (70 - 45) = mc x c x (45 - 30)
\(\frac{m_c}{m_H}\) = \(\frac{5}{3}\)
Heat lost = heat gained
mH x c x (70 - 45) = mc x c x (45 - 30)
\(\frac{m_c}{m_H}\) = \(\frac{5}{3}\)