Light of velocity 3 x 108ms-1 is incident on a material of reflective of index n. If the velocity of light is reduced to 2.4 x 108ms-1 in the material, what is n?
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Correct Answer: Option D
Explanation:
n = \(\frac{3 \times\ 10^8}{2.4 \times\ 10^8}\)
n = 1.25
n = \(\frac{3 \times\ 10^8}{2.4 \times\ 10^8}\)
n = 1.25