Two 50\(\mu\)F parallel plate capacitors are connected in series. The combined capacitor is then connected across a 100-V battery. The charge on each plate of the capacitor is
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Correct Answer: Option B
Explanation:
For series, C = \(\frac{50 \times\ 50}{50 + 50}\)
C= 25\(\mu\)F
Q = CV
Q = 25 x 100 x 10-3
Q = 2.5 x 10-3C
For series, C = \(\frac{50 \times\ 50}{50 + 50}\)
C= 25\(\mu\)F
Q = CV
Q = 25 x 100 x 10-3
Q = 2.5 x 10-3C