The power dissipated in an a.c. circuit with an r.m.s, current of 5A, r.m.s voltage of 10V and a phase angle of 60o is
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Correct Answer: Option A
Explanation:
P = IVcos\(\theta\)
= 5 x 10 x cos60
= 25W
P = IVcos\(\theta\)
= 5 x 10 x cos60
= 25W