The tendon in a man's leg is 0.01m long. If a force of 5N stretches the tendon by 2.0 x 10-5m, calculate the strain on the muscle.
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Correct Answer: Option C
Explanation:
Strain = \(\frac{extension}{\text{original length}}\)
\(\frac{2 {\times} 10^{-5}}{0.01}\)
= 2 x 10-3
Strain = \(\frac{extension}{\text{original length}}\)
\(\frac{2 {\times} 10^{-5}}{0.01}\)
= 2 x 10-3