A 500W heater is used to heat 0.6kg of water from 25oC to 100oC in t2 seconds. If another 1000W heater is used to heat 0.2kg of water from 10oC to 100oC in t, seconds, find \(\frac {t_1}{t_2}\)
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Correct Answer: Option B
Explanation:
Heat energy = Electrical energy
mc\(\theta\) = power x time
0.6 x c x (100 - 25) = 500 x t1
and, 0.2 x c x (100 - 10)= 100 x t2
\(\frac {t_1}{t_2}\) = 5
Heat energy = Electrical energy
mc\(\theta\) = power x time
0.6 x c x (100 - 25) = 500 x t1
and, 0.2 x c x (100 - 10)= 100 x t2
\(\frac {t_1}{t_2}\) = 5