A steel wire of length 0.50m is stretched between two fixed points and its fundamental frequency is 200Hz. The speed of the wave in the wire is
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Correct Answer: Option C
Explanation:
In strings, \(\lambda\) = 2L
V = F\(\lambda\)
= 200 x 2 x 0.5
= 200ms-1
In strings, \(\lambda\) = 2L
V = F\(\lambda\)
= 200 x 2 x 0.5
= 200ms-1