In the diagram above, if the internal resistance of the cell is zero, the ration of the powers P1 and P2 dissipated by R1 and R2
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Correct Answer: Option A
Explanation:
Power = IV = I2R = V[sup]2[/sup]/R
In terms of e.m.f E, of a cell we have
IE = I2R = E2/R
∴P1 = E[sup]2[/sup]/R; P2 = E[sup]2[/sup]/R[sub]2[/sub]/E[sup]2[/sup]/R[sub]2[/sub]
= E[sup]2[/sup]/R[sub]1[/sub] x R2/E2 = R2/R[sub]1[/sub]
∴P1/P[sub]2[/sub] = R2/R[sub]1[/sub]
Power = IV = I2R = V[sup]2[/sup]/R
In terms of e.m.f E, of a cell we have
IE = I2R = E2/R
∴P1 = E[sup]2[/sup]/R; P2 = E[sup]2[/sup]/R[sub]2[/sub]/E[sup]2[/sup]/R[sub]2[/sub]
= E[sup]2[/sup]/R[sub]1[/sub] x R2/E2 = R2/R[sub]1[/sub]
∴P1/P[sub]2[/sub] = R2/R[sub]1[/sub]