A sonometer wire is vibrating at frequency fo. If the tension in the wire is doubted while the length and the mass per unit length are kept constant, the new frequency of vibration is
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option D
Explanation:
For a vibrating sonometer wire, the frequency
F = l/2l √(T/m)
and if the length, l and mass per unit length, m, are constant, then Fo ∠√T => FoK√T or Fo/√T = K
=> F1o/√F[sub]1[/sub] = F2o/√F[sub]2[/sub]
∴ F1o/√T[sub]1[/sub] = F2o/√T[sub]2[/sub]
=
∴F2 = Fo x √2 = Fox√2
For a vibrating sonometer wire, the frequency
F = l/2l √(T/m)
and if the length, l and mass per unit length, m, are constant, then Fo ∠√T => FoK√T or Fo/√T = K
=> F1o/√F[sub]1[/sub] = F2o/√F[sub]2[/sub]
∴ F1o/√T[sub]1[/sub] = F2o/√T[sub]2[/sub]
| __√T1 |
=
| √T1 |
∴F2 = Fo x √2 = Fox√2